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Q.The inverse of the function f(x)=ax−1ax+1f(x) = \frac{a^x - 1}{a^x + 1} (a>0,a≠1)(a>0, a\ne1) is

a
12log⁡a(1+x1−x)\frac{1}{2} \log_a \left( \frac{1+x}{1-x} \right)
b
log⁡a(1+x1−x)\log_a \left( \frac{1+x}{1-x} \right)
c
12log⁡a(1−x1+x)\frac{1}{2} \log_a \left( \frac{1-x}{1+x} \right)
d
log⁡a(1−x1+x)\log_a \left( \frac{1-x}{1+x} \right)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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