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Q.The range of f(x)=x∣x∣+1+∣x∣x+1f(x) = \dfrac{x}{|x| + 1} + \dfrac{|x|}{x + 1} is

a
[−1,1][-1,1]
b
(0,1)(0,1)
c
[−1,0)[-1,0)
d
(-1,1)

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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The range of f(x) = \dfrac{x}{|x| + 1} + \dfrac{|x|}{x + 1}... | ParikshaNiti