Q. $\lim_{x \to 0} \dfrac{\sin 5x + \sin 3x - 2\sin 4x}{x^2}$ equals

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.lim⁡x→0sin⁡5x+sin⁡3x−2sin⁡4xx2\lim_{x \to 0} \dfrac{\sin 5x + \sin 3x - 2\sin 4x}{x^2}limx→0​x2sin5x+sin3x−2sin4x​ equals