Q. $\lim_{x \to 0} \dfrac{\log_e (1 + 6x + 9x^2)}{3x}$ equals

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Q.lim⁡x→0log⁡e(1+6x+9x2)3x\lim_{x \to 0} \dfrac{\log_e (1 + 6x + 9x^2)}{3x}limx→0​3xloge​(1+6x+9x2)​ equals