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Q.limx0xtan2x2xtanx(1cos2x)2\lim_{x \to 0} \dfrac{x \tan 2x - 2x \tan x}{(1 - \cos 2x)^2} equals

a
14\dfrac{1}{4}
b
12\dfrac{1}{2}
c
11
d
22

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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