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Q.limx0x2(cos2x+cos4x+cos6x)(sin6x)2\lim_{x \to 0} \dfrac{x^2 (\cos 2x + \cos 4x + \cos 6x)}{(\sin 6x)^2} equals

a
16\dfrac{1}{6}
b
112\dfrac{1}{12}
c
118\dfrac{1}{18}
d
124\dfrac{1}{24}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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