Q. $\lim_{x \to 0} \dfrac{\log(1 + x + x^2) + \log(1 - x + x^2)}{\sec x - \cos x}$ equals

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Q.lim⁡x→0log⁡(1+x+x2)+log⁡(1−x+x2)sec⁡x−cos⁡x\lim_{x \to 0} \dfrac{\log(1 + x + x^2) + \log(1 - x + x^2)}{\sec x - \cos x}limx→0​secx−cosxlog(1+x+x2)+log(1−x+x2)​ equals