Q.The electric field in a region is given by $\vec{E} = (300 \hat{i} + 400 \hat{j})$ N/C. The flux of this field through a square of $5$ cm on a side whose plane is parallel to the yz-plane is (JEE Main 2021)

15 Nm²/C

7.5 Nm²/C

30 Nm²/C

Zero

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The electric field in a region is given by E⃗=(300i^+400j^)\vec{E} = (300 \hat{i} + 400 \hat{j})E=(300i^+400j^​) N/C. The flux of this field through a square of 555 cm on a side whose plane is parallel to the yz-plane is (JEE Main 2021)