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Q.limx0tan3xsin3xx(tan2x+sin2x)\lim_{x \to 0} \dfrac{\tan^3 x - \sin^3 x}{x(\tan^2 x + \sin^2 x)} equals

a
12\dfrac{1}{2}
b
11
c
00
d
22

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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