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Q.limx0esinxexx3\lim_{x \to 0} \dfrac{e^{\sin x} - e^x}{x^3} equals

a
e16\dfrac{e-1}{6}
b
e6\dfrac{e}{6}
c
16\dfrac{1}{6}
d
00

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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