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Q.limx0sin(πcos2x)x2\lim_{x \to 0} \dfrac{\sin(\pi \cos^2 x)}{x^2} equals

a
π\pi
b
π2\pi^2
c
π/2\pi/2
d
2π2\pi

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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