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Q.limx0log(1+x3)+log(1x3)sin3x+sin5x\lim_{x \to 0} \dfrac{\log(1 + x^3) + \log(1 - x^3)}{\sin 3x + \sin 5x} equals

a
18\dfrac{1}{8}
b
14\dfrac{1}{4}
c
12\dfrac{1}{2}
d
11

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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