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Q.limx0sin(π[x+1])[x]\lim_{x \to 0} \dfrac{\sin(\pi [x+1])}{[x]} (where [][\cdot] is GIF) equals

a
0
b
π\pi
c
1
d
does not exist

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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