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Q.limx0ex21x2sin4x\lim_{x \to 0} \dfrac{e^{x^2} - 1 - x^2}{\sin^4 x} equals

a
12\dfrac{1}{2}
b
11
c
22
d
00

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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