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Q.limx0x2cos(sinx)xsin(cosx)x5\lim_{x \to 0} \dfrac{x^2 \cos(\sin x) - x \sin(\cos x)}{x^5} equals

a
16\dfrac{1}{6}
b
16\dfrac{-1}{6}
c
00
d
112\dfrac{1}{12}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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