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Q.limx0sin(x+2x)4x\lim_{x \to 0} \dfrac{\sin(|x| + 2x)}{4x} equals

a
12\dfrac{1}{2}
b
11
c
00
d
12\dfrac{-1}{2}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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