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Q.limx0logecos(sinx)x2\lim_{x \to 0} \dfrac{\log_e \cos(\sin x)}{x^2} equals

a
12\dfrac{-1}{2}
b
12\dfrac{1}{2}
c
00
d
11

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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