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Q.limx0log(1+sinx)log(1+x)tanxx\lim_{x \to 0} \dfrac{\log(1 + \sin x) - \log(1 + x)}{\tan x - x} equals

a
12\dfrac{1}{2}
b
11
c
00
d
\infty

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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