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Q.योग्य नित्य समानता दर्शविणारा पर्याय कोणता?

a
1x2+2+x2=(x+1x)2\frac{1}{x^{2}}+2+x^{2}=(x+\frac{1}{x})^{2}
b
1x2−x2=(1x−x)(x+1x)\frac{1}{x^{2}}-x^{2}=(\frac{1}{x}-x)(x+\frac{1}{x})
c
13x2−2+(3x2)=(13x−3x)2\frac{1}{3x^{2}}-2+(3x^{2})=(\frac{1}{3x}-3x)^{2}
d
(1x+x)2=(1x−x)2−4(\frac{1}{x}+x)^{2}=(\frac{1}{x}-x)^{2}-4

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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