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Q.limx01cos3xsin23x\lim_{x \to 0} \dfrac{1 - \cos^3 x}{\sin^2 3x} equals

a
16\dfrac{1}{6}
b
19\dfrac{1}{9}
c
118\dfrac{1}{18}
d
127\dfrac{1}{27}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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