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Q.lim⁡x→0sin⁡4x+sin⁡2x−sin⁡6xsin⁡2x−sin⁡4x+sin⁡6x\lim_{x \to 0} \dfrac{\sin 4x + \sin 2x - \sin 6x}{\sin 2x - \sin 4x + \sin 6x} equals

a
−1-1
b
00
c
11
d
22

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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\lim{x \to 0} \dfrac{\sin 4x + \sin 2x - \sin 6x}{\sin 2x ... | ParikshaNiti