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Q.limx0sin(π+x)cos(πx)sin(πx)x2\lim_{x \to 0} \dfrac{\sin(\pi + x) \cos(\pi - x) - \sin(\pi x)}{x^2} equals

a
π\pi
b
π2\pi^2
c
00
d
π/2\pi/2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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