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Q.limx0sin(π/2+x)sin(π/2x)2xx3\lim_{x \to 0} \dfrac{\sin(\pi/2 + x) - \sin(\pi/2 - x) - 2x}{x^3} equals

a
00
b
11
c
1-1
d
π\pi

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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