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Q.limx0loge1+xloge1xtanx\lim_{x \to 0} \dfrac{\log_e \sqrt{1 + x} - \log_e \sqrt{1 - x}}{\tan x} equals

a
1/21/2
b
11
c
00
d
\infty

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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