Q. $\lim_{x \to 0} \dfrac{\sin 2x + \sin 6x}{\sin 5x - \sin 3x}$ equals

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.lim⁡x→0sin⁡2x+sin⁡6xsin⁡5x−sin⁡3x\lim_{x \to 0} \dfrac{\sin 2x + \sin 6x}{\sin 5x - \sin 3x}limx→0​sin5x−sin3xsin2x+sin6x​ equals