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Q.Let f(x)={sin[πx][x]xinteger 0x=integerf(x) = \begin{cases} \dfrac{\sin[\pi x]}{[x]} & x \ne \text{integer} \ 0 & x = \text{integer} \end{cases}. Then ff is

a
continuous at every integer
b
discontinuous at every integer
c
continuous nowhere
d
continuous at non-integers only

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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