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Q.If f(x)={a∣x∣+bx<0 a+bxx≥0f(x) = \begin{cases} a|x| + b & x < 0 \ a + bx & x \ge 0 \end{cases} is differentiable everywhere, then

a
a=0,b=0a = 0, b = 0
b
a=0a = 0
c
b=0b = 0
d
no condition

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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