Q.According to Joule's Law of Heating ( $H = I^2Rt$ ), if the current flowing through a resistor is doubled while keeping the resistance and time constant, the heat generated will become:

Doubled

Halved

Four times

Remains the same

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.According to Joule's Law of Heating (H=I2RtH = I^2RtH=I2Rt), if the current flowing through a resistor is doubled while keeping the resistance and time constant, the heat generated will become: