Q.Let $f(x) = \begin{cases} \frac{\sin(\pi x)}{\tan(\pi x)} & x \ne 1/2 \ k & x = 1/2 \end{cases}$ . For continuity at $x=1/2$ , $k$ equals

-1

\pi

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.Let f(x)={sin⁡(πx)tan⁡(πx)x≠1/2 kx=1/2f(x) = \begin{cases} \frac{\sin(\pi x)}{\tan(\pi x)} & x \ne 1/2 \ k & x = 1/2 \end{cases}f(x)={tan(πx)sin(πx)​​x=1/2 k​x=1/2​. For continuity at x=1/2x=1/2x=1/2, kkk equals