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Q.The function f(x)={xsin(1/x)x0 0x=0f(x) = \begin{cases} x \sin(1/x) & x \ne 0 \ 0 & x = 0 \end{cases} is differentiable at x=0x=0 and f(0)f'(0) equals

a
0
b
1
c
1-1
d
does not exist

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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