Q.Let $f(x) = \begin{cases} 1 & x \text{ rational} \ 0 & x \text{ irrational} \end{cases}$ . Then $f$ is continuous at

all rational points

all irrational points

nowhere

everywhere

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.Let f(x)={1x rational 0x irrationalf(x) = \begin{cases} 1 & x \text{ rational} \ 0 & x \text{ irrational} \end{cases}f(x)={1​x rational 0​x irrational​. Then fff is continuous at