Q.The function $f(x) = \begin{cases} \frac{\tan 3x - \tan x}{1 + 3\tan^2 x} & x \ne 0 \ k & x = 0 \end{cases}$ is continuous at $x=0$ if $k$ equals

1

\dfrac{1}{3}

3

0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The function f(x)={tan⁡3x−tan⁡x1+3tan⁡2xx≠0 kx=0f(x) = \begin{cases} \frac{\tan 3x - \tan x}{1 + 3\tan^2 x} & x \ne 0 \ k & x = 0 \end{cases}f(x)={1+3tan2xtan3x−tanx​​x=0 k​x=0​ is continuous at x=0x=0x=0 if kkk equals