Q.Let $f(x) = \begin{cases} x & |x| \le 1 \ \frac{1}{x} & |x| > 1 \end{cases}$ . Then $f$ is

continuous everywhere

continuous except at

x=\pm1

differentiable everywhere

none

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.Let f(x)={x∣x∣≤1 1x∣x∣>1f(x) = \begin{cases} x & |x| \le 1 \ \frac{1}{x} & |x| > 1 \end{cases}f(x)={x​∣x∣≤1 x1​​∣x∣>1​. Then fff is