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Q.If f(x)={1cos4xx2x<0 ax=0 xx>0f(x) = \begin{cases} \frac{1 - \cos 4x}{x^2} & x < 0 \ a & x = 0 \ \sqrt{x} & x > 0 \end{cases} is continuous at x=0x=0, then aa equals

a
8
b
16
c
4
d
2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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