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Q.The function f(x)={x+5x<0 x2+5x0f(x) = \begin{cases} x + 5 & x < 0 \ x^2 + 5 & x \ge 0 \end{cases} is continuous at x=0x=0 and differentiable at x=0x=0 if

a
true
b
false
c
only continuous
d
only differentiable

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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The function f(x) = \begin{cases} x + 5 & x < 0 \\ x^2 + 5 ... | ParikshaNiti