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Q.Let f(x)={sin⁡(πx)x−1x≠1 kx=1f(x) = \begin{cases} \dfrac{\sin(\pi x)}{x-1} & x \ne 1 \ k & x = 1 \end{cases}. For what value of kk is ff continuous at x=1x=1?

a
π\pi
b
00
c
11
d
−π-\pi

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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