Q.Let $f(x) = \begin{cases} \dfrac{\tan(\pi(x - [x]))}{1 - 2[x]} & x \notin \mathbb{Z} \ 0 & x \in \mathbb{Z} \end{cases}$ . Then $f$ is continuous at

every integer

no integer

only even integers

only odd integers

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.Let f(x)={tan⁡(π(x−[x]))1−2[x]x∉Z 0x∈Zf(x) = \begin{cases} \dfrac{\tan(\pi(x - [x]))}{1 - 2[x]} & x \notin \mathbb{Z} \ 0 & x \in \mathbb{Z} \end{cases}f(x)={1−2[x]tan(π(x−[x]))​​x∈/Z 0​x∈Z​. Then fff is continuous at