Q.The function $f(x) = \begin{cases} x & x \text{ rational} \ 0 & x \text{ irrational} \end{cases}$ is continuous at

x=0

only

all rational points

nowhere

all irrational points

The correct solution involves applying the fundamental concept to derive the final value step by step...

Already a member? Login here

Q.The function f(x)={xx rational 0x irrationalf(x) = \begin{cases} x & x \text{ rational} \ 0 & x \text{ irrational} \end{cases}f(x)={x​x rational 0​x irrational​ is continuous at