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Q.If f(x)={1cos2xx2x0 kx=0f(x) = \begin{cases} \frac{1 - \cos 2x}{x^2} & x \ne 0 \ k & x = 0 \end{cases} is continuous at x=0x=0, then kk equals

a
1
b
2
c
4
d
8

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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