The function $f(x) = \begin{cases} x^2 & x 0 \end{cases}$ is

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Q.The function $f(x) = \begin{cases} x^2 & x < 0 \ 0 & x = 0 \ x & x > 0 \end{cases}$ is

continuous everywhere

continuous at

x=0

only

discontinuous at

x=0

continuous except at

x=0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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