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Q.If f(x)={sinxxx0 1x=0f(x) = \begin{cases} \frac{\sin x}{x} & x \ne 0 \ 1 & x = 0 \end{cases}, then f(0)f'(0) equals

a
0
b
1
c
-1
d
does not exist

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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If f(x) = \begin{cases} \frac{\sin x}{x} & x \ne 0 \\ 1 & x... | ParikshaNiti