Q.The function $f(x) = \begin{cases} x^2 & x \le 0 \ \sqrt{x} & x > 0 \end{cases}$ is continuous at $x=0$

Yes

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Only from left

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Q.The function f(x)={x2x≤0 xx>0f(x) = \begin{cases} x^2 & x \le 0 \ \sqrt{x} & x > 0 \end{cases}f(x)={x2​x≤0 x​​x>0​ is continuous at x=0x=0x=0