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Q.If f(x)={x2−1x−1x≠1 kx=1f(x) = \begin{cases} \frac{x^2 - 1}{x-1} & x \ne 1 \ k & x = 1 \end{cases}, then for continuity at x=1x=1, kk equals

a
2
b
1
c
0
d
-2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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