Q.The function $f(x) = \begin{cases} x^2 & x \le 0 \ |x| & x > 0 \end{cases}$ is continuous at $x=0$ and differentiable at $x=0$

True

False

Only continuous

Only differentiable

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The function f(x)={x2x≤0 ∣x∣x>0f(x) = \begin{cases} x^2 & x \le 0 \ |x| & x > 0 \end{cases}f(x)={x2​x≤0 ∣x∣​x>0​ is continuous at x=0x=0x=0 and differentiable at x=0x=0x=0