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Q.Let f(x)={sin(πx)x(x2)x0,2 ax=0 bx=2f(x) = \begin{cases} \frac{\sin(\pi x)}{x(x-2)} & x \ne 0,2 \ a & x = 0 \ b & x = 2 \end{cases}. For continuity at x=0x=0 and x=2x=2, aa and bb are

a
π/2,π/2\pi/2, \pi/2
b
π/2,π/2\pi/2, -\pi/2
c
0,00, 0
d
π,π\pi, \pi

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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