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Q.If f(x)={log(1+ax)xx0 bx=0f(x) = \begin{cases} \frac{\log(1+ax)}{x} & x \ne 0 \ b & x = 0 \end{cases} is continuous at x=0x=0, then bb equals

a
a
b
log a
c
eae^a
d
0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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