Q.The function $f(x) = \begin{cases} x & x \text{ rational} \ x^2 & x \text{ irrational} \end{cases}$ is continuous at

x=0,1

x=1 only

x=0 only

nowhere

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The function f(x)={xx rational x2x irrationalf(x) = \begin{cases} x & x \text{ rational} \ x^2 & x \text{ irrational} \end{cases}f(x)={x​x rational x2​x irrational​ is continuous at