Home/Question #2620
PracticeMedium

Q.Let f(x)={x2x≤0 ax+bx>0f(x) = \begin{cases} x^2 & x \le 0 \ ax + b & x > 0 \end{cases}. If ff is differentiable everywhere, then

a
a=0,b=0a = 0, b = 0
b
a=0a = 0
c
b=0b = 0
d
no real values

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here