Q.The function $f(x) = \begin{cases} \dfrac{\sin x}{x} & x \ne 0 \ 0 & x = 0 \end{cases}$ is differentiable at $x=0$

True

False

Only from right

Only from left

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The function f(x)={sin⁡xxx≠0 0x=0f(x) = \begin{cases} \dfrac{\sin x}{x} & x \ne 0 \ 0 & x = 0 \end{cases}f(x)={xsinx​​x=0 0​x=0​ is differentiable at x=0x=0x=0