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Q.The function f(x)={sinxxx0 1x=0f(x) = \begin{cases} \frac{\sin x}{x} & x \ne 0 \ 1 & x = 0 \end{cases} is continuous at x=0x=0. Its derivative at x=0x=0 is

a
0
b
1
c
does not exist
d
-1

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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